HOLT PHYSICS PROBLEM 2B

Text of Holt Physics Problem 2B - woodard/HP_chap2_sect2/ of 0.19 m/s2 for the ship to reach its optimal rate...

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Problem 2B 5

NAME ______________________________________ DATE _______________ CLASS ____________________

Holt Physics

Problem 2BAVERAGE ACCELERATION

P R O B L E MIn 1977 off the coastline of Australia, the fastest speed by a vessel on the waterwas accomplished. If this vessel were to undergo an average acceleration of1.80 m/s2, it would certainly go from remainder to its peak rate in 85.6 s. What was thespeed of the vessel?

S O L U T I O N

Given: aavg = 1.80 m/s2

t = 85.6 svi = 0 m/s

Unknown: vf = ?

Use the definition of average acceleration to uncover vf.

aavg =

v

t =

vf

t

vi

Rearvariety the equation to calculate vf.

vf = aavg t + vi

vf = 1.80 ms285.6 s + 0 ms= 154

m

s

= 154 ms 3.60 1h103 s

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ADDITIONAL PRACTICE

1. If the vessel in the sample difficulty accelerates for 1.00 min, what willits rate be after that minute? Calculate the answer in both meters per

second and kilometers per hour.

2. In 1935, a French destroyer, La Awful, attained among the fastestspeeds for any type of standard warship. Suppose it took 2.0 min at a constant

acceleration of 0.19 m/s2 for the ship to reach its optimal speed after start-

ing from remainder. Calculate the ships last speed.

See more: Wunderlich-Malec Engineering

3. In 1934, the wind rate on Mt. Washington in New Hampshiregot to a document high. Suppose a very sturdy glider is released in this

wind, so that in 45.0 s the glider reaches the rate of the wind. If the

Holt Physics Problem Workbook6

NAME ______________________________________ DATE _______________ CLASS ____________________

glider undergoes a continuous acceleration of 2.29 m/s2, what is the

winds speed? Assume that the glider is initially at rest.

4. In 1992, Maurizio Damilano, of Italy, walked 29 752 m in 2.00 h.a. Calculate Damilanos average rate in m/s.b. Suppose Damilano slows down to 3.00 m/s at the midpoint in his

journey, yet then picks up the pace and accelerates to the speed

calculated in (a). It takes Damilano 30.0 s to accelerate. Find the

magnitude of the average acceleration in the time of this time interval.

5. South African frogs are capable of jumping as much as 10.0 m in one hop.Suppose among these frogs renders precisely 15 of these jumps in a time

interval of 60.0 s.

a. What is the frogs average velocity?b. If the frog lands via a velocity equal to its average velocity and

involves a full speak 0.25 s later on, what is the frogs average

acceleration?

6. In 1991 at Smith College, in Massachusetts, Ferdie Adoboe ran 1.00 102 m backward in 13.6 s. Suppose it takes Adoboe 2.00 s toachieve a velocity equal to her average velocity in the time of the run. Find

her average acceleration during the initially 2.00 s.

7. In the 1992 Summer Olympics, the Gerguy four-guy kayak team cov-ered 1 km in just under 3 minutes. Suppose that in between the starting

point and the 150 m note the kayak steadily rises its rate from

0.0 m/s to 6.0 m/s, so that its average rate is 3.0 m/s.

a. How lengthy does it take to cover the 150 m?b. What is the magnitude of the average acceleration in the time of that

part of the course?

8. The greatest speed ever achieved on a bicycle was reached by JohnHoward of the USA. The bicycle, which was accelerated by

being towed by a automobile, got to a velocity of +245 km/h. Suppose

Howard desires to slow-moving down, and also applies the brakes on his now freely

moving bicycle. If the average acceleration of the bicycle throughout brak-

ing is 3.0 m/s2, exactly how lengthy will it take for the bicycles velocity to de-

crease by 20.0 percent?

9. In 1993, bicyclist Rebecca Twigg of the United States traveled 3.00 kmin 217.347 s. Suppose Twigg travels the entire distance at her average

speed and that she then increases at 1.72 m/s2 to come to a complete

stop after crossing the end up line. How long does it take Twigg to come

to a stop?

10. During the Winter Olympic games at Lillehammer, Norway, in 1994,Dan Jansen of the USA skated 5.00 102 m in 35.76 s. Sup-pose it takes Jansen 4.00 s to rise his velocity from zero to his