A sliding crate of fruit mastering physics

Homework-related Statement

A cprice of fruit through a mass of 33.5kg and also a details warm capacity of 3650 J/kg*K slides 8.20m dvery own a ramp inclined at an angle of 37.6 levels listed below the horizontal.If an amount of heat equal to the magnitude of the work-related done by friction is took in by the cprice of fruit and also the fruit reaches a unidevelop last temperature, what is its temperature change ?

Homework-related Equations

Change in temperature = gLsin(theta)/c - v^2/2c

The Attempt at a Solution

I am doing the following equation over and also I am getting a response of -3.00 * 10^-3 and it keeps saying it is wrong. I am not certain what I am doing wrong. I have it erected favor this:9.81*8.2*sin(37.6)/3650 - (2.4)^2/(2)(3650)Any aid would certainly be appreciated, thanks!

Homejob-related Statement

A cprice of fruit with a mass of 33.5kg and also a specific heat capacity of 3650 J/kg*K slides 8.20m dvery own a ramp inclined at an angle of 37.6 levels below the horizontal.If an amount of heat equal to the magnitude of the occupational done by friction is took in by the cprice of fruit and the fruit reaches a unidevelop final temperature, what is its temperature change ?

Homework Equations

Change in temperature = gLsin(theta)/c - v^2/2c

The Attempt at a Solution

I am doing the adhering to equation over and I am acquiring a solution of -3.00 * 10^-3 and it keeps saying it is wrong. I am not certain what I am doing wrong. I have it erected choose this:9.81*8.2*sin(37.6)/3650 - (2.4)^2/(2)(3650)Any aid would certainly be appreciated, thanks!
Oh sorry that was offered in the previous question as its speed:If the crate was at rest at the optimal of the incline and also has a rate of 2.40 m/s at the bottom
Oh sorry that was provided in the previous question as its speed:If the cprice was at remainder at the peak of the incline and has actually a rate of 2.40 m/s at the bottom
Okay. Well, your calculation approach looks okay then. Check that your calculator is collection for levels and also not radians for angle computations.

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Okay. Well, your calculation strategy looks okay then. Check that your calculator is collection for levels and also not radians for angle computations.
Yeah, I did, and it still says its wrong. I gained this as a tip on MasterPhysics:Remember to use radians, not degrees, in debates to trigonometric attributes.So I tried to usage Radians rather and obtained -.000789 and that"s wrong as well, lol.
Well you know that the temperature of the cprice need to climb because it"s soaking up heat energy. So any negative worth you calculate is bound to be incorrect. You need to still be having actually a calculator worry. Break the calculation into components and also let"s watch your intermediate outcomes.
Well you know that the temperature of the cprice have to climb because it"s soaking up warmth power. So any type of negative value you calculate is bound to be incorrect. You should still be having a calculator problem. Break the calculation right into components and let"s watch your intermediate results.
True. Because it claims to use radians, I did:9.81*8.2*sin(37.6) and also gained -7.9597. Than I separated that by 3650 and gained -.0021807. Than I subtracted (2.4)^2 from that and obtained -5.7622. Than I divided it by 2*3650 and also obtained -.000789.

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If you"re going to use radians then the angle that you supply will have to be in radians! You"ve provided the angle in levels. Either transform the angle to radians before taking the sine, or adjust your calculator to accept levels. You don"t HAVE to usage radians if you"re given the angles in levels to begin with; use whichever calculator mode suits the offered trouble.
Than I split that by 3650 and obtained -.0021807. Than I subtracted (2.4)^2 from that and gained -5.7622. Than I divided it by 2*3650 and also gained -.000789.
You should calculate the whole second term prior to you subtract it from the first one. The calculator will perform the operations in the order entered; it does not understand about your formula"s layout on paper, it"ll subtract 2.42 from the initially term and also then divide the result by 2 and also then that result by 3650. That"s not what you intfinished...
If you"re going to usage radians then the angle that you supply will need to be in radians! You"ve offered the angle in levels. Either transform the angle to radians prior to taking the sine, or adjust your calculator to accept levels. You don"t HAVE to usage radians if you"re provided the angles in levels to begin with; usage whichever calculator mode suits the offered problem.You need to calculate the whole second term before you subtract it from the first one. The calculator will perform the operations in the order entered; it does not know about your formula"s layout on paper, it"ll subtract 2.42 from the initially term and also then divide the outcome by 2 and also then that result by 3650. That"s not what you intended...
Alappropriate I did what you sassist and got .0134469-.000789 and also got .01. That is still wrong tho, lmao. I do not obtain what I am doing wrong.
Alappropriate I did what you sassist and got .0134469-.000789 and also got .01. That is still wrong tho, lmao. I don"t get what I am doing wrong.